Nuclear Weapon Counts

General Wednesday 27th July 2005

I was reading defense tech the other day and noticed this in an article:

…of the 12,500 targets in the SIOP at that time, one of them was slated to be hit by 69 consecutive nuclear weapons.

69!? for one target! How on earth did they work that out?

…the highest kill probability for the United States’ best weapon against deeply buried, sprawling, hardened command posts was less than 5%. Blair got out a calculator, assumed a kill probability of 4% for one weapon, and started multiplying. To attain a 50% confidence in destroying the target required 17 weapons. When Blair got up to 69 weapons, the “kill probability” had reached 94%.

wow, that’s some real smart thinking!

Read the whole article.


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